(0.102+x)/(1.428-2x)^2=0.1004

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Solution for (0.102+x)/(1.428-2x)^2=0.1004 equation: 



(0.102+x)/(1.428-2x)^2=0.1004

We move all terms to the left:

(0.102+x)/(1.428-2x)^2-(0.1004)=0



Domain of the equation: (1.428-2x)^2!=0

x∈R



We add all the numbers together, and all the variables

(x+0.102)/(-2x+1.428)^2-(0.1004)=0

We add all the numbers together, and all the variables

(x+0.102)/(-2x+1.428)^2-0.1004=0

We multiply all the terms by the denominator


(x+0.102)-(0.1004)*(-2x+1.428)^2=0

We get rid of parentheses

x-(0.1004)*(-2x+1.428)^2+0.102=0

We move all terms containing x to the left, all other terms to the right

x-(0.1004)*(-2x+1.428)^2=-0.102

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